Use the Limit Comparison Test to determine whether the series converges or diverges. n=1∑∞5n−4n1 Identify bn in the f
Posted: Thu Jul 14, 2022 4:28 pm
Use the Limit Comparison Test to determine whether the series converges or diverges. n=1∑∞5n−4n1 Identify bn in the following limit. n→∞limbnan=n→∞lim5n−4n1=L Since L a finite number, L0, and bn is
n=1∑∞5(1+1/n)n(1+1/n)1 Identify bn in the following limit. n→∞limbnan=n→∞lim5(1+1/n)n(1+1/n)1=L Since L a finite number, L0, and bn is
Use the Limit Comparison Test to determine whether the series converges or diverges. n=1∑∞(1−cos(n1)) Identify bn in the following limit. n→∞limbnan=n→∞lim1−cos(n1)=L Since L a finite number, L0, and bn is
Does n=2∑∞(ln(n))p1 converge if p is large enough? If so, for which p ? The series diverges for all p by comparison with the harmonic series. The series converges for all p by comparison with the harmonic series. The series diverges for p>2. The series converges as p approaches infinity. The series converges for p<2.
n=1∑∞5(1+1/n)n(1+1/n)1 Identify bn in the following limit. n→∞limbnan=n→∞lim5(1+1/n)n(1+1/n)1=L Since L a finite number, L0, and bn is
Use the Limit Comparison Test to determine whether the series converges or diverges. n=1∑∞(1−cos(n1)) Identify bn in the following limit. n→∞limbnan=n→∞lim1−cos(n1)=L Since L a finite number, L0, and bn is
Does n=2∑∞(ln(n))p1 converge if p is large enough? If so, for which p ? The series diverges for all p by comparison with the harmonic series. The series converges for all p by comparison with the harmonic series. The series diverges for p>2. The series converges as p approaches infinity. The series converges for p<2.