A particle moves according to a law of motion s=f(t),t≥0, where t is measured in seconds and s in feet. f(t)=t3−15t2+72t
Posted: Thu Jul 14, 2022 4:26 pm
- A Particle Moves According To A Law Of Motion S F T T 0 Where T Is Measured In Seconds And S In Feet F T T3 15t2 72t 1 (6.74 KiB) Viewed 39 times
- A Particle Moves According To A Law Of Motion S F T T 0 Where T Is Measured In Seconds And S In Feet F T T3 15t2 72t 2 (4.73 KiB) Viewed 39 times
- A Particle Moves According To A Law Of Motion S F T T 0 Where T Is Measured In Seconds And S In Feet F T T3 15t2 72t 3 (11.01 KiB) Viewed 39 times
A particle moves according to a law of motion s=f(t),t≥0, where t is measured in seconds and s in feet. f(t)=t3−15t2+72t
(e) Find the total distance (in feet) traveled during the first 7 s. ×ft
1) When, for 0≤t<∞, is the particle speeding up? (Enter your answer using interval notation.) र When, for 0≤t<∞, is it slowing down? (Enter your answer using interval notation.)