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k=1∑∞(9k1−9k+21) k=1∑∞(1+k4)5k k=1∑∞k2+4k+31
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k=1∑∞(9k1−9k+21) k=1∑∞(1+k4)5k k=1∑∞k2+4k+31
Posted:
Thu Jul 14, 2022 4:22 pm
by
answerhappygod
K 1 9k1 9k 21 K 1 1 K4 5k K 1 K2 4k 31 1 (16.85 KiB) Viewed 40 times
k=1∑∞(9k1−9k+21) k=1∑∞(1+k4)5k k=1∑∞k2+4k+31