Answer Happy

In the theory of relativity, the Lorentz contraction formula L=L0​1−c2v2​​ expresses the length L of an object as a function of its velocity v with res Find v→c−lim​L. Why is a left-hand limit necessary? L is not defined for v<0. L is not defined for v>0. L is not defined for v>C. L is not defined for v<c. −/0.83 Points] SCALCET9 2.3.011. Evaluate the limit, if it exists. (If an answer does not exist, enter DNE.) x→−8lim​(7x−5)
(a) What is wrong with the following equation? x−4x2+x−20​=x+5(x−4)(x+5)=x2+x−20​ The left-hand side is not defined for x=0, but the right-hand side is. The left-hand side is not defined for x=4, but the right-hand side is. None of these − the equation is correct. (b) In view of part (a), explain why the following equation is correct. x→4lim​x−4x2+x−20​=x→4lim​(x+5) Since x−4x2+x−20​ and x+5 are both continuous, the equation follows. Since the equation holds for all x=4, it follows that both sides of the equation approach the same limit as x→4. This equation follows from the fact that the equation in part (a) is correct. None of these − the equation is not correct.
(a) Evaluate each limit. (i) x→−9lim​Ix] (ii) x→−9lim​[[x]] (iii) x→−9.4lim​IxI (b) If n is an integer, evaluate each limit. (i) x→π−lim​[[xx (ii) x→n+lim​[[x]] The limit exists for all positive values of a. The limit exists only for a=0. The limit exists for all non-integer values of a. The limit exists for all integer values of a.
Evaluate the limit, if it exists. (If an answer does not exist, enter DNE.) x→6lim​x2−3x−18x2+3x​ −10.83 Points] SCALCET9 2.3.023. Evaluate the limit, if it exists. (If an answer does not exist, enter DNE.) h→0lim​h25+h​−5​