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(1.) ∫(6x3−4x+x−1)dx (2.) ∫(4ex+2x)dx (3.) ∫(9t3t2+7​)dt (4.) ∫(ln(t)5t​)dt (a.) ∫t1​dt (b.) 4ex+2xln(2)+C (c.) 25t2​t1​

Posted: Thu Jul 14, 2022 4:10 pm
by answerhappygod
1 6x3 4x X 1 Dx 2 4ex 2x Dx 3 9t3t2 7 Dt 4 Ln T 5t Dt A T1 Dt B 4ex 2xln 2 C C 25t2 T1 1
1 6x3 4x X 1 Dx 2 4ex 2x Dx 3 9t3t2 7 Dt 4 Ln T 5t Dt A T1 Dt B 4ex 2xln 2 C C 25t2 T1 1 (38.01 KiB) Viewed 39 times
(1.) ∫(6x3−4x+x−1)dx (2.) ∫(4ex+2x)dx (3.) ∫(9t3t2+7​)dt (4.) ∫(ln(t)5t​)dt (a.) ∫t1​dt (b.) 4ex+2xln(2)+C (c.) 25t2​t1​+C (d.) 23x4​−2x2+ln∣x∣+C (e.) 5ln∣lnt∣+C (f.) 69​(3t2+7)23​+C (g.) (3t2+7)23​+C