(1.) ∫(6x3−4x+x−1)dx (2.) ∫(4ex+2x)dx (3.) ∫(9t3t2+7)dt (4.) ∫(ln(t)5t)dt (a.) ∫t1dt (b.) 4ex+2xln(2)+C (c.) 25t2t1
Posted: Thu Jul 14, 2022 4:10 pm
(1.) ∫(6x3−4x+x−1)dx (2.) ∫(4ex+2x)dx (3.) ∫(9t3t2+7)dt (4.) ∫(ln(t)5t)dt (a.) ∫t1dt (b.) 4ex+2xln(2)+C (c.) 25t2t1+C (d.) 23x4−2x2+ln∣x∣+C (e.) 5ln∣lnt∣+C (f.) 69(3t2+7)23+C (g.) (3t2+7)23+C