Find the solution of the given initial value problem: y(4)+2y′′+y=5t+10;y(0)=y′(0)=0,y′′(0)=y(3)(0)=1. y(t)=(−9+23t)cos
Posted: Thu Jul 14, 2022 4:08 pm
Find the solution of the given initial value problem: y(4)+2y′′+y=5t+10;y(0)=y′(0)=0,y′′(0)=y(3)(0)=1. y(t)=(−9+23t)cos(t)+(2−11−4t)sin(t)+5t+10