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Give the solution of 9-11, I need the solution at 11:00 pm.Thank you
CALCULUS 1: ASSIGNMENT NO. 4 9. y=(sinx)cosx Answer: y′=(sinx)cosx−1[cos2x−sin2xln(sinx)] 10. y=(cos−1x)lnx2 Answer: y′=(cos−1x)lnx2−1[x1−x2​−xlnx2+ln(cos−1x)(cos−1x)2(1−x2​)​] 11. y=(sinhx)cosx Answer: (sinhx)cosx−1[(cosxcoshx−sinxsinhxln(sinhx)] 12. y=x8(x+2)6(x+1)2(x−1)4​ Answer: y′=x8(x+2)6(x+1)2(x−1)4​[x+12​+x−14​−x8​−x+26​] y′=x9(x+2)7−2(x+1)(x−1)3​[4x3+x2+9x−8]