Answer Happy • Find the solution of the given initial value problem: y(4)+2y′′+y=5t+10;y(0)=y′(0)=0,y′′(0)=y(3)(0)=1. y(t)=(−10+2t)cos

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Find the solution of the given initial value problem: y(4)+2y′′+y=5t+10;y(0)=y′(0)=0,y′′(0)=y(3)(0)=1. y(t)=(−10+2t)cos

Posted: Thu Jul 14, 2022 4:04 pm

by answerhappygod

: Find The Solution Of The Given Initial Value Problem Y 4 2y Y 5t 10 Y 0 Y 0 0 Y 0 Y 3 0 1 Y T 10 2t Cos 1 (26.71 KiB) Viewed 36 times

Find the solution of the given initial value problem: y(4)+2y′′+y=5t+10;y(0)=y′(0)=0,y′′(0)=y(3)(0)=1. y(t)=(−10+2t)cos(t)+(−7+21t)sin(t)+5t+10