Consider the following equation: 4⋅x2−x+6=4⋅x2⋅p−3 If p=1 this is a quadratic equation and therefore has either one, tw
Posted: Thu Jul 14, 2022 3:47 pm
Consider the following equation: 4⋅x2−x+6=4⋅x2⋅p−3 If p=1 this is a quadratic equation and therefore has either one, two or no solutions. Determine for what values of p the equation has two solutions in x ? Give your answer in the form p>α or p<α for some number a. We exclude the value p=1 for the reason explained above. ∧p=1
Recall that we have the equation: 4⋅x2−x+6=4⋅x2⋅p−3 Let p=6. Solve the equation for x. Give your answer in the form: none if there is no solution, x=x1 if there is one solution, x=x1∨x=x2 if there are two solutions. Use the correct values for x1 and x1.
Recall that we have the equation: 4⋅x2−x+6=4⋅x2⋅p−3 Let p=6. Solve the equation for x. Give your answer in the form: none if there is no solution, x=x1 if there is one solution, x=x1∨x=x2 if there are two solutions. Use the correct values for x1 and x1.