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Consider the following equation: 4⋅x2−x+6=4⋅x2⋅p−3 If p=1 this is a quadratic equation and therefore has either one, tw

Posted: Thu Jul 14, 2022 3:47 pm
by answerhappygod
Consider The Following Equation 4 X2 X 6 4 X2 P 3 If P 1 This Is A Quadratic Equation And Therefore Has Either One Tw 1
Consider The Following Equation 4 X2 X 6 4 X2 P 3 If P 1 This Is A Quadratic Equation And Therefore Has Either One Tw 1 (13 KiB) Viewed 36 times
Consider The Following Equation 4 X2 X 6 4 X2 P 3 If P 1 This Is A Quadratic Equation And Therefore Has Either One Tw 2
Consider The Following Equation 4 X2 X 6 4 X2 P 3 If P 1 This Is A Quadratic Equation And Therefore Has Either One Tw 2 (21.13 KiB) Viewed 36 times
Consider The Following Equation 4 X2 X 6 4 X2 P 3 If P 1 This Is A Quadratic Equation And Therefore Has Either One Tw 3
Consider The Following Equation 4 X2 X 6 4 X2 P 3 If P 1 This Is A Quadratic Equation And Therefore Has Either One Tw 3 (21.13 KiB) Viewed 36 times
Consider the following equation: 4⋅x2−x+6=4⋅x2⋅p−3 If p=1 this is a quadratic equation and therefore has either one, two or no solutions. Determine for what values of p the equation has two solutions in x ? Give your answer in the form p>α or p<α for some number a. We exclude the value p=1 for the reason explained above. ∧p=1
Recall that we have the equation: 4⋅x2−x+6=4⋅x2⋅p−3 Let p=6. Solve the equation for x. Give your answer in the form: none if there is no solution, x=x1​ if there is one solution, x=x1​∨x=x2​ if there are two solutions. Use the correct values for x1​ and x1​.