Answer Happy

(1) Solve the following boundary value and/or initial value problems (1) dxdy​+5x4y2=0 with 1c:y(0)=1 (2) y′′−9y=0 with ICS: y(0)=2 and y′(0)=−1 (3) y′′+4y=0 with BCS: y(0)−2 and y(π/u)=10 solve the following POE (u) ∂t∂u​=k∂x2∂2u​ with BCS:u(0,t)=0,u(L,t)=0 and ic: ∪(x,0)=f(x)