c) The following result in Table Q2 was obtained from consolidated undrained test on specimens of overconsolidated clay.
Posted: Thu Jul 14, 2022 3:00 pm
c) The following result in Table Q2 was obtained from consolidated undrained test on specimens of overconsolidated clay. Based on Table Q2; (i) Plot Mohr's circles of effective stress. (8 marks) (ii) Determine friction angle, ϕ and cohesion, C for effectives stress (4 marks) (iii) Calculate angle θ that the failure plane makes with the major principle plane. (3 marks)
TABLE Q2: Result from consolidated undrained test on overconsolidated clay
EQUATION LIST T=π×cα×(2D2×L+6D2) γ=VwW ρd=1+ SsW4G2ρw γd=1+100w(%)γ γd=1+SGswGdZˉs τ′=c+σn′tanϕ′ E= M old Volume Number of Blow/ ayer × Number of Layer × Weig α1=a3tan2(45∘+2ϕ)+2ctan(45∘+2ϕ) σ3=σ1tan2(45∘−2ϕ)−2ctan(45∘−2ϕ) σa=2σ1+σs+2σ1−σ3cos2θqi=Akαii τf=2σ1−σ3sin2θk=Aiq k=2.303 Ata Llog= h2h1kka4=kdkx k= AhuQ Li=LΔh k=2.727H(ht−hr)qlog10(trn)k=π(h12−h22)2.303qlog11(t2n)
TABLE Q2: Result from consolidated undrained test on overconsolidated clay
EQUATION LIST T=π×cα×(2D2×L+6D2) γ=VwW ρd=1+ SsW4G2ρw γd=1+100w(%)γ γd=1+SGswGdZˉs τ′=c+σn′tanϕ′ E= M old Volume Number of Blow/ ayer × Number of Layer × Weig α1=a3tan2(45∘+2ϕ)+2ctan(45∘+2ϕ) σ3=σ1tan2(45∘−2ϕ)−2ctan(45∘−2ϕ) σa=2σ1+σs+2σ1−σ3cos2θqi=Akαii τf=2σ1−σ3sin2θk=Aiq k=2.303 Ata Llog= h2h1kka4=kdkx k= AhuQ Li=LΔh k=2.727H(ht−hr)qlog10(trn)k=π(h12−h22)2.303qlog11(t2n)