Answer Happy

For the shape shown above, which moment of inertia would be a larger value, Ix or ly? a) ly b) 1x c) Neither, they would be equal  Cartesian Vectors  Magnitude: ​F=Fx​i+Fy​j+F2​k^F=Fx2​+Fy2​+Fz2​​​ Position Vector: rAB​​=(xB​−xA​)f^​+(yR​−yA​)j^​+(zB​−xA​)k^ Unit vector: QF​=pf​=rrx​​i+Fr2​​j+rrL​​k =cosαi^+cosβj^​+cosγk^∘ To convert a scalar force into Cartesian form: F=Fn^=F(rr​) Dot Product: A⋅B=ABcosθ=Ax​Bx​+Ay​By​+Az​Bz​ To find thesingle between 2 veckes: θ=cos−1(ABAz​θx​+Ay​By​+Az​Hz​​) To find the projoction of a vactor along a lind: F⋅Δine​=Rx​ux​+Fy​uy​+Rg​uz​ Moments To find the moment about a point (Cross Product - unswer is a veclor): M˙=r×F=∣∣​i^rz​Fx​​i^ry​Fy​​k^rz​F2​​∣∣​=(ry​Fz​−r2​Fy​)(−(rx​Fz​−r2​Fx​))+(rx​Fy​−ry​Fz​)k 'To find the monent ahout a line or axis ("Triplo Scalar Itoduct" answer is a scalar): M=tuiav​​−ri×F2=∣∣​ux​rx​Fx​​uy​ry​Fy​​uz​rx​Fz​​∣∣​=(ry​Fx​−ry​Fy​)ux​−(rx​Fx​−rz​Fx​)uy​+(rx​Fy​−ry​Fx​)ud​ lo put this in Cartokian form: M=Mθilas ​ Simplificution of a Porce und Couple Systam: Pk​=∑F and (MN​)α​=ΣM+ΣMα​ Systems of Forces and Minents Fequilibrica of a Particle, ∑P∗​=0;∑Py​=0;∑Rr​=0 Eujulibrium of a 2D Rigid Bixly, ∑Rx​=0;ΣFy​=0;ΣMa​=0 |2 Havoe Miember| Concurrent Forces: A concurrant forse systcm is one which the linis of aution of the forecs all noer at cas poinh. Imleterminate Structure: A arruelus that han mors unknowns then wailable squations of equilitrium. Stable ithucture: Stubility requires there he enough reactions to suppod the applied foadn, and that those reactions are fist all parallel or octcument.