Q = 400 KG R = 1*106 S = 3600 RPM
Posted: Thu Jul 14, 2022 2:52 pm
Q = 400 KG
R = 1*106
S = 3600 RPM
A general basic vibratory system consists of mass and spring. Figure Q1 shows the vibration knowledge application of multiple parallel springs installed in between the Caterpillar diesel engine generator and the foundation slab (inside the red dash box). Given that the mass of the diesel engine generator is W=Qkg, the spring equivalent stiffness is keq=RN/m and the generator revolution per minute is RPM=S RPM. Assume that the system is a single degree of freedom and undergoes only vertical translational movement.
(i) Sketch free body diagram of the system together with the action and reaction force magnitude and direction. (ii) Compare the value of spring displacement, x for the free vibration and force vibration of 10kN if the diesel engine generator excites 1 m/s2 during operation. Neglect the gravitational effect. (iii) Determine the number of cycles per second for the diesel engine generator.
R = 1*106
S = 3600 RPM
- Q 400 Kg R 1 106 S 3600 Rpm 1 (39.03 KiB) Viewed 55 times
(i) Sketch free body diagram of the system together with the action and reaction force magnitude and direction. (ii) Compare the value of spring displacement, x for the free vibration and force vibration of 10kN if the diesel engine generator excites 1 m/s2 during operation. Neglect the gravitational effect. (iii) Determine the number of cycles per second for the diesel engine generator.