Problem at the bottom and given notes. THANKS IN ADVANCE:) UPVOTE
Posted: Tue Apr 26, 2022 5:32 pm
Problem at the bottom and given notes. THANKS IN ADVANCE:) UPVOTE
Laguerre Note on simplifying the terms in the previous series: (n + k + 1)(n+k) ... (n-3)(x - 2)(n-1) = 1-2-34.0+(nk+1).(-1) 12-34..(+) Laguerre solution from Bedient () One solution: ya = E*- *CER 40x* = Ln(x) Laguerre polynomial yı is valid for all finite x except x = 0 The associated logarithmic solution is: yz = L(x)lnx + 1 (2)x(Hn-e-Hn-20xx (-1) (k-1)xk (KD [(x+10) Where (-1) (1)*n! & H, = 1+$+$ + -- +8= 2L (n-1) V2 is valid for x > 0 Solution: y = ALOx+By, Use the value of n in y + ΣΤ1 Bedient uses the shorthand notation given in the previou slide. He gives the logarithmic solution obtained after *considerable simplification with finite series ending & the other being a Infinite series. PROBLEM: x?y" + *(1-x)y' +2579 50 x²yx(=
Laguerre Note on simplifying the terms in the previous series: (n + k + 1)(n+k) ... (n-3)(x - 2)(n-1) = 1-2-34.0+(nk+1).(-1) 12-34..(+) Laguerre solution from Bedient () One solution: ya = E*- *CER 40x* = Ln(x) Laguerre polynomial yı is valid for all finite x except x = 0 The associated logarithmic solution is: yz = L(x)lnx + 1 (2)x(Hn-e-Hn-20xx (-1) (k-1)xk (KD [(x+10) Where (-1) (1)*n! & H, = 1+$+$ + -- +8= 2L (n-1) V2 is valid for x > 0 Solution: y = ALOx+By, Use the value of n in y + ΣΤ1 Bedient uses the shorthand notation given in the previou slide. He gives the logarithmic solution obtained after *considerable simplification with finite series ending & the other being a Infinite series. PROBLEM: x?y" + *(1-x)y' +2579 50 x²yx(=