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Q: Mass Hanging From Two Strings in the Limit Abokimark this page Consider the Free Body Diagram (FBD) analysis of a mass hanging on two ropes as seen in the diagram below in the case when θ2​=π rad −θ1​
0.0H0.0 points (graded) Draw the FBD's for the hanging mass and consider what happens as the angle θ1​ takes various limits while the angle θ2​ is constrained by θ2​=πrad−θ1​. Select the correct statements. As the angle θ1​ increases from zero the angle θ2​ increases from zero. As the angle θ1​ increases from zero the angle θ2​ decreases from π/2rad. As the angle θ1​ increases from zero the angle θ2​ decreases from n rad. The tension in the rope which has angle θ1​ is less than the tension in the rope which has angle θ2​. The tension in the rope which has angle θ1​ is equal to the tension in the rope which has angle θ2​. The tension in the rope which has angle θ1​ is greater than the tension in the rope which has angle θ2​. As the angle θ1​ increases from zero the tension in the rope at angle θ1​ increases from zero. As the angie θ1​ increases from zero the tension in the rope at angle θ1​ increases from a non-zero value. As the angle θj​ increases from zero the tension in the rope at angle θ1​ decreases from a non-zero value. As the angle θ1​ increases from zero the tension in the rope at angle θ1​ decreases from infinity.
Consider the Free Body Diagram (FBD) analysis of a block of mass m>0, sliding in the direction shown on a ramp having coefficlent of kinet friction μ and angle θ to the horizontal, in gravity of acceleration g. Let FN​ be the magnitude of the normal force, and let FD​ be the downhil component of the body force. The goal is to calculate the acceleration of the block. Gravity and Friction 0.0/10.0 points (graded) Draw the FBD for the block and use it to calculate the acceleration of the block. Select the correct statements. When FD​>μFN​ the block's speed is increasing. When FD​>μFN​ the block's speed is decreasing. When FD​<μFN​ the blocks speed is increasing. When FD​<μFN​ the block's speed is decreasing When FD​>μFN​ the magnitude of the total force on the block is FD​−μFN​. When FD​>μFN​ the magnitude of the fotal force on the block is FD​+μFN​ - When FD​<μFN​ the magnitude of the total force on the block is μFN​−FD​. When FD​<μFN​ the magnitude of the total force on the block is μFN​+FD​.