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2. dt3d3y+2dt2d2y−9dtdy−18=10+20sin5t
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2. dt3d3y+2dt2d2y−9dtdy−18=10+20sin5t
Posted:
Thu Jul 14, 2022 2:37 pm
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answerhappygod
2 Dt3d3y 2dt2d2y 9dtdy 18 10 20sin5t 1 (46.5 KiB) Viewed 24 times
2. dt3d3y+2dt2d2y−9dtdy−18=10+20sin5t