41.) What is XXXXXXXX |01101001? 41.answer) X11X1XX1 42.) What is XXXXXXXX &00110101? 42.answer) 00XX
Posted: Thu Jul 14, 2022 2:13 pm
41.) What is XXXXXXXX |01101001?41.answer)X11X1XX142.) What is XXXXXXXX &00110101?42.answer)00XX0X0X43.) What is XXXXXXXX |01110110?43.answer)44.) What is XXXXXXXX &11011011?44.answer)For the following three questions, remember that bit numbers startnumbering from 0, and that hexadecimal numbers are always unsigned.In addition to showing the mask you would use, also show the operationyou would use, like so: &0x0020. (i.e., AND the original number withthe hexadecimal mask 0x0020.)45.) Specify the mask you would need to isolate bit 0 of the unknown number. The result of the operation should be 0 (0x0000) if bit 0 is 0, and non-zero if bit 0 is 1. Express it as a 4-digit hexadecimal number.45.answer)&0x000146.) Specify the mask you would need to set bit 1 of the unknown number to zero. That is, the result of this operation results in a new number, which the unknown number will be subsequently set to. Express it as a 4-digit hexadecimal number.46.answer)&0xFFFD47.) Specify the mask you would need to inspect bit 4 of the unknown number. The result of the operation should be 0 (0x0000) if bit 4 is 0, and non-zero if bit 4 is 1. Express it as a 4-digit hexadecimal number.47.answer)48.) Specify the mask you would need to inspect bit 8 of the unknown number. The result of the operation should be 0 (0x0000) if bit 8 is 0, and non-zero if bit 8 is 1. Express it as a 4-digit hexadecimal number.48.answer)49.) Specify the mask you would need to set bit 7 of the unknown number to zero. That is, the result of this operation results in a new number, which the unknown number will be subsequently set to. Express it as a 4-digit hexadecimal number.49.answer)50.) Specify the mask you would need to set bit 7 of the unknown number to one. That is, the result of this operation results in a new number, which the unknown number will be subsequently set to. Express it as a 4-digit hexadecimal number.50.answer)