If xi=total number of nonconformities in a sample of ni inspection units, and there are N samples of different sample si
Posted: Thu Jul 14, 2022 1:53 pm
a) \(\bar{u} = \frac{\sum_{i=1}^N \frac{2x_i}{n_i}}{N}\)
b) \(\bar{u} = \frac{\sum_{i=1}^N \frac{x_i}{2n_i}}{2N}\)
c) \(\bar{u} = \frac{\sum_{i=1}^N \frac{x_i}{n_i}}{N}\)
d) \(\bar{u} = \frac{\sum_{i=1}^N \frac{x_i}{n_i}}{2N}\)
b) \(\bar{u} = \frac{\sum_{i=1}^N \frac{x_i}{2n_i}}{2N}\)
c) \(\bar{u} = \frac{\sum_{i=1}^N \frac{x_i}{n_i}}{N}\)
d) \(\bar{u} = \frac{\sum_{i=1}^N \frac{x_i}{n_i}}{2N}\)