UM Tb 50°C Ty 28°C h = 6 W/mK k 0.35 W/mK Q = 17.5 40.078 2k Critical Thicknessic 0.116 Thickness=ro- ri where ro is vol
Posted: Tue Apr 26, 2022 4:10 pm
UM Tb 50°C Ty 28°C h = 6 W/mK k 0.35 W/mK Q = 17.5 40.078 2k Critical Thicknessic 0.116 Thickness=ro- ri where ro is volved from following equation 1 Ank Anekh (", -) +hro - 4.0 Heat flow without insulation = 0 17 =hA(T. -Ty) = 6 x 0.078(50 - 28) = 10.296 To 1 R= + Ankron Auroh Heat flow with insulation = Q = To - Ty R