= 1. Consider a square region between 0
Posted: Tue Apr 26, 2022 4:08 pm
- 1 Consider A Square Region Between 0 X A And Y A As Shown In The Following Figure The Boundary At X 0 Is Kept Insu 1 (281.93 KiB) Viewed 43 times
Please provide clear steps and don't copy from other responses. Thanks in advance
= 1. Consider a square region between 0<x<a and (<y<a as shown in the following figure. The boundary at x=0 is kept insulated, and boundary at x =a and y=0 is dissipating heat by convection to an environment with temperature Too with heat transfer coefficient of h. Boundary at y = b is kept at constant temperature of T. a. Write the finite -difference form of the steady state heat conduction equations of (d’T/dx?) +(d’T/dy?) +g/k = 0) Where g is constant source and K is thermal conductivity., and for each 12 nodes where temperature Tn, where N = 1 to 12 are to be determined. b. Derive system of equations to solve for all In's and show them in determinate form. = Prescribed temperatures fo 12 L Convection boundary 27 ax Insulated boundary dT dx 0 kathl=rt. TS TO Tg T12 To T2 15 11 2 11 14 Convection boundary -k OT +ht=hT By
Posted: Tue Apr 26, 2022 4:08 pm
- 1 Consider A Square Region Between 0 X A And Y A As Shown In The Following Figure The Boundary At X 0 Is Kept Insu 1 (281.93 KiB) Viewed 43 times
= 1. Consider a square region between 0<x<a and (<y<a as shown in the following figure. The boundary at x=0 is kept insulated, and boundary at x =a and y=0 is dissipating heat by convection to an environment with temperature Too with heat transfer coefficient of h. Boundary at y = b is kept at constant temperature of T. a. Write the finite -difference form of the steady state heat conduction equations of (d’T/dx?) +(d’T/dy?) +g/k = 0) Where g is constant source and K is thermal conductivity., and for each 12 nodes where temperature Tn, where N = 1 to 12 are to be determined. b. Derive system of equations to solve for all In's and show them in determinate form. = Prescribed temperatures fo 12 L Convection boundary 27 ax Insulated boundary dT dx 0 kathl=rt. TS TO Tg T12 To T2 15 11 2 11 14 Convection boundary -k OT +ht=hT By