Answer Happy

Posted: **Tue Apr 26, 2022 4:00 pm**

: L 0 2m Ri 0 015m Tb 50 C Ty 28 C H 6 W Mk K 0 35 W Mk Q 17 5 A 0 078 2 K Critical Thickness To 0 116 H 1 (47.71 KiB) Viewed 37 times

: L 0 2m Ri 0 015m Tb 50 C Ty 28 C H 6 W Mk K 0 35 W Mk Q 17 5 A 0 078 2 K Critical Thickness To 0 116 H 2 (47.71 KiB) Viewed 37 times

- L = 0.2m ri = 0.015m Tb = 50°C Ty = 28°C h = 6 W/mK k = 0.35 W/mK Q = 17.5 A = 0.078 2 k Critical Thickness to 0.116 h Thickness = x = ro ri where ro is solved from following equation (To-Ty 1 470kh a - Antkr) +hr, -k = 0 Heat flow without insulation - a 17 = hA(To – Ty) = 6 x 0.078(50 – 28) = 10.296 R. то - та 1 + 4nkror Anrh Heat flow with insulation = Q To - Ty R