- L = 0.2m ri = 0.015m Tb = 50°C Ty = 28°C h = 6 W/mK k = 0.35 W/mK 0 = 17.5 A = 0.078 2k Critical Thickness to h 0.116
Posted: Tue Apr 26, 2022 4:00 pm
- L 0 2m Ri 0 015m Tb 50 C Ty 28 C H 6 W Mk K 0 35 W Mk 0 17 5 A 0 078 2k Critical Thickness To H 0 116 1 (44.09 KiB) Viewed 45 times
- L 0 2m Ri 0 015m Tb 50 C Ty 28 C H 6 W Mk K 0 35 W Mk 0 17 5 A 0 078 2k Critical Thickness To H 0 116 2 (44.09 KiB) Viewed 45 times
- L = 0.2m ri = 0.015m Tb = 50°C Ty = 28°C h = 6 W/mK k = 0.35 W/mK 0 = 17.5 A = 0.078 2k Critical Thickness to h 0.116 А ri = 0.078 471 0.078 47 Thickness = x ro - ri where ro is solved from following equation 17 Ankh To - Ty e 73 + hry - k = 0 4 kr Heat flow without insulation e = hA(To - Ty) = 6 x 0.078(50 - 28) = 10.296 - + To - Ti 1 R = 4rtkror: 4trh To - Ty Heat flow with insulation Q = R