needed to hold the rod in equilibrium. 3 m 6 m 400 N 37- 300 N x 2 m 80 F: Applied forces FReaction force at A=F(A),comp
Posted: Tue Apr 26, 2022 3:30 pm
- Needed To Hold The Rod In Equilibrium 3 M 6 M 400 N 37 300 N X 2 M 80 F Applied Forces Freaction Force At A F A Comp 1 (66.54 KiB) Viewed 39 times
needed to hold the rod in equilibrium. 3 m 6 m 400 N 37- 300 N x 2 m 80 F: Applied forces FReaction force at A=F(A),components are A(x), A(y) A(z) Ty : Tension force in cable BC=T(BC) Ignore weight of the member AB. Express the tension force in cable BC? A) T(BC) vector=(-8/7)T(BC)i+(3/7)T(BC)j+(2/7)T(BC)k B) T(BC) vector=(1/7)T(BC)i+(-2/7)T(BC) (3/7)T(BC)k C) T(BC) vector=(-3/5)T(BC)+(2/5)T(BC)+(6/5)T(BC) D) T(BC) vector=(6/13)T(BC)i+(3/13)T(BC)]+(2/13)T(BC)k E) TIBO vectora 4.17TBC+(245) TIBC (15/113) TIB.Cik