The correct relation between the emitter current Ie and the base current Ib is given by
Posted: Thu Jul 14, 2022 12:13 pm
a) Ib = (1 + α) Ie
b) Ib = (α – 1) Ie
c) Ie = (1 – ß) Ib
d) Ie = (1 + ß) Ib
b) Ib = (α – 1) Ie
c) Ie = (1 – ß) Ib
d) Ie = (1 + ß) Ib