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Posted: **Tue Apr 26, 2022 3:02 pm**

: Question 35 1 Point Using Superposition Theorem What Is The Voltage On The 300 Resistor Due To E2 Supply Only E1 10 1 (172.56 KiB) Viewed 19 times

: Question 35 1 Point Using Superposition Theorem What Is The Voltage On The 300 Resistor Due To E2 Supply Only E1 10 2 (200.32 KiB) Viewed 19 times

: Question 35 1 Point Using Superposition Theorem What Is The Voltage On The 300 Resistor Due To E2 Supply Only E1 10 3 (156.44 KiB) Viewed 19 times

: Question 35 1 Point Using Superposition Theorem What Is The Voltage On The 300 Resistor Due To E2 Supply Only E1 10 4 (263.42 KiB) Viewed 19 times

: Question 35 1 Point Using Superposition Theorem What Is The Voltage On The 300 Resistor Due To E2 Supply Only E1 10 5 (215.51 KiB) Viewed 19 times

: Question 35 1 Point Using Superposition Theorem What Is The Voltage On The 300 Resistor Due To E2 Supply Only E1 10 6 (255.01 KiB) Viewed 19 times

Question 35 (1 point) Using superposition theorem, what is the voltage on the 300 resistor due to E2 supply only? E1=10 V and E2 - 4 V. 100 El 200 300 E2 + w 4000 1.45 V G O 0.97V O 1.94V None of these answers. 1.69 V O 1.21 V Question 36 (1 point) A 9
Question 34 (1 point) Using superposition theorem, what is the voltage on the 300 Q resistor due to E1 supply only? E1=10 V and E2 = 4 V. 10Ο Ω w El 200 ΩΣ 300 0 E2 w 4000 1.35 V 01.16 None of these answers. 1.55 V O 1.94 V O 1.74 V Question 35 (1 point) Using superposition theorem, what is the voltage on the 300 Q resistor due to E2 cunnlv.only? 1-10V and 2A 0 0
Question 36 (1 point) Using Superposition theorem, what is the total voltage on the 300 resistor? E1 = 10 V and E2 = 4 V. 1000 w E1 200 03 300 g E2 w 4000 3.88 V 2.56 V O 3v 0 2.13 v None of these answers. 0 3.43 v inctinn 27.11 ninti cu А ܝܐ
Question 43 (1 point) Using mesh analysis, solve for the current 1 19 20 10V 93 2 5V 32 O-SA -2.5 A 了 2.5 A 0 -2.27A None of these answers. Question 44 (1 point) Which is the correct mesh equation around loop 2 for the fo O
Question 44 (1 point) Which is the correct mesh equation around loop 2 for the following diagram 192 w 20 w 10V g 3 5V 3Ω 031 - 512=-10 0-412 - 512= 15 O-41₂ - 512 = -15 Thing None of these answers. 0 31 - 512= 10 Question 45 (1 point) Using mesh analysis, solve for the current 11. 122 M 222 M
Question 45 (1 point) Using mesh analysis, solve for the currently 10 20 10V 29+ 5V 0625 mA 0-625 mA G -455 mA None of these answers. 0-5 mA Question 46 (1 point) Saved OSA