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Given the z-transform pair \(X[n] \leftrightarrow \frac{32}{z^2-16}\), |z|<4 The z-transform of the signal y[n] = \(\fra

Posted: Thu Jul 14, 2022 11:09 am
by answerhappygod
a) \(\frac{(z+2)^2}{(z+2)^2-16}\)
b) \(\frac{z^2}{z^2-4}\)
c) \(\frac{(z-2)^2}{(z-2)^2-16}\)
d) \(\frac{z^2}{z^2-64}\)