Find the inverse Laplace transform for the function X(s) = \(\frac{1+e^{-2s}}{3s^2+2s}\).
Posted: Thu Jul 14, 2022 11:09 am
a) e-(2/3)t u(t) – u(t) + e-(2/3)(t-2) u(t-2)-u(t-2)
b) e-(2/3)t u(t) + e-(2/3)(t-2) u(t-2)
c) e-(2/3)(t-2) u(t-2) – u(t-2)
d) e-(2/3)t u(t) – u(t)
b) e-(2/3)t u(t) + e-(2/3)(t-2) u(t-2)
c) e-(2/3)(t-2) u(t-2) – u(t-2)
d) e-(2/3)t u(t) – u(t)