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Find the inverse Laplace transform of X(s) = \(\frac{s}{s^2 a^2+b^2}\).

Posted: Thu Jul 14, 2022 11:09 am
by answerhappygod
a) \(\frac{1}{a^2} \,cos⁡(\frac{a}{b})t\)
b) \(\frac{1}{a^2} \,cos⁡(\frac{b}{a})t\)
c) \(\frac{1}{a^2} \,sin⁡(\frac{b}{a})t\)
d) \(\frac{1}{a^2} \,sin⁡(\frac{a}{b})t\)