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Determine the initial value x(0+) for the Laplace transform X(s) = \(\frac{4}{s^2+3s-5}\).
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Determine the initial value x(0+) for the Laplace transform X(s) = \(\frac{4}{s^2+3s-5}\).
Posted:
Thu Jul 14, 2022 11:09 am
by
answerhappygod
a) -1
b) 0
c) 1
d) ∞