X (ejω) = \(\frac{(b-a) e^{jω}}{e^{-j2ω}-(a+b) e^{jω} + ab)}\), |b|<1<|a| The value of x[n] is __________
Posted: Thu Jul 14, 2022 11:09 am
a) bn u [n] + an u [n-1]
b) bn u [n] – an u [-n-1]
c) bn u [n] + an u [-n-1]
d) bn u [n] – an u [n+1]
b) bn u [n] – an u [-n-1]
c) bn u [n] + an u [-n-1]
d) bn u [n] – an u [n+1]