For a T-network if the Open circuit impedance parameters are given as z11, z21, z12, z22, then z11 in terms of Inverse H
Posted: Thu Jul 14, 2022 11:02 am
a) z12 = \(\frac{1}{g_{11}} \)
b) z12 = – \(\frac{g_{12}}{g_{11}} \)
c) z12 = – \(\frac{g_{21}}{g_{11}} \)
d) z12 = \(\left(g_{22} – \frac{g_{21} g_{12}}{g_{11}}\right)\)
b) z12 = – \(\frac{g_{12}}{g_{11}} \)
c) z12 = – \(\frac{g_{21}}{g_{11}} \)
d) z12 = \(\left(g_{22} – \frac{g_{21} g_{12}}{g_{11}}\right)\)