For a T shaped network, if the Short-circuit admittance parameters are y11, y12, y21, y22, then y12 in terms of Inverse
Posted: Thu Jul 14, 2022 11:02 am
a) y12 = \(\frac{A’}{B’}\)
b) y12 = – \(\frac{1}{B’}\)
c) y12 = \(\left(C’ – \frac{D’ A’}{B’}\right)\)
d) y12 = \(\frac{D’}{B’}\)
b) y12 = – \(\frac{1}{B’}\)
c) y12 = \(\left(C’ – \frac{D’ A’}{B’}\right)\)
d) y12 = \(\frac{D’}{B’}\)