The inverse Laplace transform of F(s) = \(\frac{5}{s^2-9}\) is ______________
Posted: Thu Jul 14, 2022 10:59 am
a) \(\frac{1}{6}e^{3t} + \frac{5}{6e^{-3t}}\)
b) \(\frac{1}{6}e^{3t} – \frac{5}{6e^{-3t}}\)
c) \(\frac{5}{6}e^{3t} + \frac{5}{6e^{-3t}}\)
d) \(\frac{5}{6}e^{3t} – \frac{5}{6e^{-3t}}\)
b) \(\frac{1}{6}e^{3t} – \frac{5}{6e^{-3t}}\)
c) \(\frac{5}{6}e^{3t} + \frac{5}{6e^{-3t}}\)
d) \(\frac{5}{6}e^{3t} – \frac{5}{6e^{-3t}}\)