Consider the circuit shown below. On applying the Kirchhoff’s current law, the equation will be?
Posted: Thu Jul 14, 2022 10:59 am
a) V/(2s-15)+(V-[(100/s)+30])/(3s+10)=0
b) V/(2s-15)+(V-[(100/s)+30])/(3s-10)=0
c) V/(2s+15)+(V-[(100/s)+30])/(3s+10)=0
d) V/(2s+15)+(V-[(100/s)+30])/(3s-10)=0
b) V/(2s-15)+(V-[(100/s)+30])/(3s-10)=0
c) V/(2s+15)+(V-[(100/s)+30])/(3s+10)=0
d) V/(2s+15)+(V-[(100/s)+30])/(3s-10)=0