In the circuit shown below, the switch is closed at t = 0, applied voltage is v (t) = 50cos (102t+π/4), resistance R = 1
Posted: Thu Jul 14, 2022 10:59 am
a) i = c exp (-t/10-5) – (4.99×10-3) cos(100t+π/2+89.94o)
b) i = c exp (-t/10-5) + (4.99×10-3) cos(100t+π/2+89.94o)
c) i = -c exp(-t/10-5) + (4.99×10-3) cos(100t+π/2+89.94o)
d) i = -c exp(-t/10-5) – (4.99×10-3) cos(100t+π/2+89.94o)
b) i = c exp (-t/10-5) + (4.99×10-3) cos(100t+π/2+89.94o)
c) i = -c exp(-t/10-5) + (4.99×10-3) cos(100t+π/2+89.94o)
d) i = -c exp(-t/10-5) – (4.99×10-3) cos(100t+π/2+89.94o)