In the circuit shown below, the switch is closed at t = 0, applied voltage is v (t) = 50cos (102t+π/4), resistance R = 1
Posted: Thu Jul 14, 2022 10:59 am
a) ip = (4.99×10-3) cos(100t+π/4-89.94o)
b) ip = (4.99×10-3) cos(100t-π/4-89.94o)
c) ip = (4.99×10-3) cos(100t-π/4+89.94o)
d) ip = (4.99×10-3) cos(100t+π/4+89.94o)
b) ip = (4.99×10-3) cos(100t-π/4-89.94o)
c) ip = (4.99×10-3) cos(100t-π/4+89.94o)
d) ip = (4.99×10-3) cos(100t+π/4+89.94o)