The expression of current from the circuit shown below.
Posted: Thu Jul 14, 2022 10:59 am
a) i=e-200t [c1 cos979.8t+c2 979.8t]A
b) i=e200t [c1 cos979.8t-c2 979.8t]A
c) i=e-200t [c1 cos979.8t-c2 979.8t]A
d) i=e200t [c1 cos979.8t+c2 979.8t]A
b) i=e200t [c1 cos979.8t-c2 979.8t]A
c) i=e-200t [c1 cos979.8t-c2 979.8t]A
d) i=e200t [c1 cos979.8t+c2 979.8t]A