a) 100 = 20i + 0.05 \(\frac{di}{dt} + \frac{1}{20 \times 10^{-6}} \int idt\)
b) 100 = 20i – 0.05 \(\frac{di}{dt} + \frac{1}{20 \times 10^{-6}} \int idt\)
c) 100 = 20i + 0.05 \(\frac{di}{dt} – \frac{1}{20 \times 10^{-6}} \int idt\)
d) 100 = 20i – 0.05 \(\frac{di}{dt} – \frac{1}{20 \times 10^{-6}} \int idt\)
The circuit shown in the figure consists of resistance, capacitance and inductance in series with a 100V source when the
-
answerhappygod
- Site Admin
- Posts: 899604
- Joined: Mon Aug 02, 2021 8:13 am
The circuit shown in the figure consists of resistance, capacitance and inductance in series with a 100V source when the
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!