a) I‘=((I1R1+I2R2+⋯.+InRn))/(R1+R2+⋯Rn)
b) I’=I1R1+I2R2+⋯.+InRn
c) I’=((I1/R1+I2/R2+⋯.+In/Rn))/(R1+R2+⋯Rn)
d) I’=I1/R1+I2/R2+⋯.+In/Rn
According to Millman’s Theorem, if there are n current sources with n internal conductances respectively, are in series,
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answerhappygod
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According to Millman’s Theorem, if there are n current sources with n internal conductances respectively, are in series,
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