The cut off frequency of a waveguide with resonant cavity is given by

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answerhappygod
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The cut off frequency of a waveguide with resonant cavity is given by

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a) V√((m/a)2 + (n/b)2 + (p/d)2)/2
b) V√((m/a)2 + (n/b)2 + (p/d)2)
c) 2V√((m/a)2 + (n/b)2 + (p/d)2)
d) V√((m/a) + (n/b) + (p/d))/2
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