T=T = 1045 Lly = 1345 cm V - 5 Ho = 458 cm/V-s n = 1.5x100cm = T= 300 K SOP
Posted: Tue Apr 26, 2022 2:04 pm
- T T 1045 Lly 1345 Cm V 5 Ho 458 Cm V S N 1 5x100cm T 300 K Sop 1 (1.36 KiB) Viewed 38 times
- T T 1045 Lly 1345 Cm V 5 Ho 458 Cm V S N 1 5x100cm T 300 K Sop 2 (1.6 KiB) Viewed 38 times
equilibrium.
(b) Assuming a low level of excitation, the recombination factor
αr=?
(c) The excess carrier concentration in under steady state
condition δn,δp = ?
- T T 1045 Lly 1345 Cm V 5 Ho 458 Cm V S N 1 5x100cm T 300 K Sop 3 (914 Bytes) Viewed 38 times
Lly = 1345 cm V - 5
Ho = 458 cm/V-s n = 1.5x100cm = T= 300 K
SOP