- The Two Systems 2x1 X2 3 4x1 3x2 5 And 2x1 X2 1 4x1 3x2 1 Have The Same Coefficient Matrix But Differ 1 (171.73 KiB) Viewed 64 times
The two systems 2x1 + x2 = 3 4x1 + 3x2 = 5 and 2x1 + x2 = = -1 4x1 + 3x2 1 = have the same coefficient matrix but differ
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The two systems 2x1 + x2 = 3 4x1 + 3x2 = 5 and 2x1 + x2 = = -1 4x1 + 3x2 1 = have the same coefficient matrix but differ
The two systems 2x1 + x2 = 3 4x1 + 3x2 = 5 and 2x1 + x2 = = -1 4x1 + 3x2 1 = have the same coefficient matrix but different right-hand sides. Solve both systems simultaneously by eliminating the first entry in the second row of the augmented matrix: - [2 13 4 35 318 17 1 and then performing back substitutions for each of the columns corresponding to the right-hand sides.