a) High-boost filtering reduces to regular Highpass filtering
b) High-boost filtering reduces to regular Lowpass filtering
c) All of the mentioned
d) None of the mentioned
High boost filtered image is expressed as: fhb = A f(x, y) – flp(x, y), where f(x, y) the input image, A is a constant a
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answerhappygod
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High boost filtered image is expressed as: fhb = A f(x, y) – flp(x, y), where f(x, y) the input image, A is a constant a
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