Given below is a differential amplifier in which V1=V2. What happens to VOIB at this condition?
Posted: Thu Jul 14, 2022 10:01 am
a) VOIB= 0
b) VOIB= VOIB×10-10
c) VOIB= VOIB/2
d) VOIB= -1
b) VOIB= VOIB×10-10
c) VOIB= VOIB/2
d) VOIB= -1