a) VOIB= 0
b) VOIB= VOIB×10-10
c) VOIB= VOIB/2
d) VOIB= -1
Given below is a differential amplifier in which V1=V2. What happens to VOIB at this condition?
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answerhappygod
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Given below is a differential amplifier in which V1=V2. What happens to VOIB at this condition?
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