What is the reconstruction formula for the bandpass signal x(t) with samples taken at the rate of 2B samples per second?
Posted: Thu Jul 14, 2022 9:46 am
a) \(\sum_{m=-\infty}^{\infty}x(mT)\frac{sin(π/2T) (t-mT)}{(π/2T)(t-mT)} cos2πF_c (t-mT)\)
b) \(\sum_{m=-\infty}^{\infty}x(mT)\frac{sin(π/2T) (t+mT)}{(π/2T)(t+mT)} cos2πF_c (t-mT)\)
c) \(\sum_{m=-\infty}^{\infty}x(mT)\frac{sin(π/2T) (t-mT)}{(π/2T)(t-mT)} cos2πF_c (t+mT)\)
d) \(\sum_{m=-\infty}^{\infty}x(mT)\frac{sin(π/2T) (t+mT)}{(π/2T)(t+mT)} cos2πF_c (t+mT)\)
b) \(\sum_{m=-\infty}^{\infty}x(mT)\frac{sin(π/2T) (t+mT)}{(π/2T)(t+mT)} cos2πF_c (t-mT)\)
c) \(\sum_{m=-\infty}^{\infty}x(mT)\frac{sin(π/2T) (t-mT)}{(π/2T)(t-mT)} cos2πF_c (t+mT)\)
d) \(\sum_{m=-\infty}^{\infty}x(mT)\frac{sin(π/2T) (t+mT)}{(π/2T)(t+mT)} cos2πF_c (t+mT)\)