Find the inverse Z – Transform of \(log \frac{z}{z+1}\).
Posted: Thu Jul 14, 2022 9:41 am
a) \(\frac{(-1)^n}{n} \)
b) \(\frac{(-1)^{n+1}}{n} \)
c) \(\frac{1}{n} \)
d) \(\frac{(-1)^n}{n+1} \)
b) \(\frac{(-1)^{n+1}}{n} \)
c) \(\frac{1}{n} \)
d) \(\frac{(-1)^n}{n+1} \)