Find the Fourier Cosine Transform of F(x) = 2x for 0
Posted: Thu Jul 14, 2022 9:41 am
a) \(fc(p) = \frac{32}{(p^2 π^2)} (cos(pπ)-1)p \) not equal to 0 and if equal to 0 \( fc(p) = 16 \)
b) \(fc(p) = \frac{32}{(p^2 π^2)} (cos(pπ)-1)p \) not equal to 0 and if equal to 0 \( fc(p) = 32 \)
c) \(fc(p) = \frac{64}{(pπ^2)} (cos(pπ)-1)p \) not equal to 0 and if equal to 0 \( fc(p) = 16 \)
d) \(fc(p) = \frac{32}{(pπ^2)} (cos(pπ)-1)p \) not equal to 0 and if equal to 0 \( fc(p) = 64 \)
Posted: Thu Jul 14, 2022 9:41 am
a) \(fc(p) = \frac{32}{(p^2 π^2)} (cos(pπ)-1)p \) not equal to 0 and if equal to 0 \( fc(p) = 16 \)
b) \(fc(p) = \frac{32}{(p^2 π^2)} (cos(pπ)-1)p \) not equal to 0 and if equal to 0 \( fc(p) = 32 \)
c) \(fc(p) = \frac{64}{(pπ^2)} (cos(pπ)-1)p \) not equal to 0 and if equal to 0 \( fc(p) = 16 \)
d) \(fc(p) = \frac{32}{(pπ^2)} (cos(pπ)-1)p \) not equal to 0 and if equal to 0 \( fc(p) = 64 \)
b) \(fc(p) = \frac{32}{(p^2 π^2)} (cos(pπ)-1)p \) not equal to 0 and if equal to 0 \( fc(p) = 32 \)
c) \(fc(p) = \frac{64}{(pπ^2)} (cos(pπ)-1)p \) not equal to 0 and if equal to 0 \( fc(p) = 16 \)
d) \(fc(p) = \frac{32}{(pπ^2)} (cos(pπ)-1)p \) not equal to 0 and if equal to 0 \( fc(p) = 64 \)