Find the solution of \(\frac{∂u}{∂x}=36 \frac{∂u}{∂t}+10u \) if \( \frac{∂u}{∂x} (t=0)=3e^{-2x} \) using the method of s
Posted: Thu Jul 14, 2022 9:41 am
a) \(\frac{-3}{2} e^{-2x} e^{-t/3}\)
b) \(3e^x e^{-t/3} \)
c) \(\frac{3}{2} e^{2x} e^{-t/3} \)
d) \(3e^{-x} e^{-t/3} \)
b) \(3e^x e^{-t/3} \)
c) \(\frac{3}{2} e^{2x} e^{-t/3} \)
d) \(3e^{-x} e^{-t/3} \)