Find the general solution of the linear partial differential equation, yzp+zxq=xy.

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answerhappygod
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Find the general solution of the linear partial differential equation, yzp+zxq=xy.

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a) φ(x2-y2 – z2 )=0
b) φ(x2-y2, y2-z2 )=0
c) φ(x2-y2, y2-x2 )=0
d) φ(x2-z2, z2-x2 )=0
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